MathlibAnnex.CStarAlgebra.CAR.iInf_range_atomic_transportedFlag_eq_span
theorem
Assembles the matching and inequivalent fiber calculations in an arbitrary Hilbert direct sum.
Statement
For a fixed shell family and as below, let and . Denote the coordinate embedding by . Then , where .
Assumptions
Let be the completed CAR algebra, the completion of the matrix stages under . Write for the image of the first diagonal matrix unit. These are decreasing projections with . Write for the canonical embedding of stage . The root state is determined by on every stage.
Choose one pure state from each unitary-equivalence class of pure-state Gelfand-Naimark-Segal (GNS) representations, retaining at the root index . Write for its complete complex GNS space, unital star representation and unit cyclic vector. Thus , and the vectors are dense in . Inner products are linear in the second argument.
A fixed shell family supplies unital complex star automorphisms and elements with , , and . At the root, is the identity and . Fix and put . The family is supplied; its existence is not an extra conclusion here. The Hilbert direct sum consists of square-summable families , and acts coordinatewise. No countability of is assumed. The coordinate embedding is isometric, so is a unit vector.
Conclusion
The orthogonal projection onto this common range is the rank-one map . The decreasing-projection theorem therefore gives strong convergence of to this map. In the construction of the shell unitaries, this is the one-dimensional residual space joined to the root residual line when the difference-shell maps are completed to a unitary.
The exact declaration is the equality of subspaces, and its identity remains separate from the two fiber declarations. The rank-one and strong-limit assertions are explained consequences. The coordinate proof works for an arbitrary index set; it does not exchange an uncountable sum with a limit or assert operator-norm convergence.
Proof route
A vector is in the range of an orthogonal projection exactly when that projection fixes it. Thus a vector belongs to the common range exactly when every coordinate is fixed by all . The matching-fiber common-range theorem forces to be a scalar multiple of , while the inequivalent-fiber common-range theorem forces for . Conversely, the embedded vector and all its scalar multiples are fixed by every .
Proof steps
For a vector in the common range, apply each coordinate evaluation to . This gives fixedness in every fiber without a sum-limit argument.
The common projection in fiber sends to ; since is fixed it equals that value. For , the common projection is zero, so fixedness gives . Therefore .
Every flag projection fixes in the matching fiber. Acting coordinatewise therefore fixes every scalar multiple of , proving the reverse inclusion. The unit norm then identifies the projection onto the resulting line.
Main citations
Lean source signature (exact)
theorem iInf_range_atomic_transportedFlag_eq_span
(family : RepresentativeShellFamily) (i : MathlibAnnex.CStarAlgebra.PureState.GNSClass Limit) :
(⨅ n, (atomicRepresentation
(MathlibAnnex.CStarAlgebra.PureState.selectedRepresentation completedRootPureState)
(transportedFlag family i n)).range) =
ℂ ∙ MathlibAnnex.CStarAlgebra.PureState.selectedEmbedding completedRootPureState i
(MathlibAnnex.CStarAlgebra.PureState.selectedVector completedRootPureState i)
| In the source | Mathematical meaning |
|---|---|
family; i : GNSClass Limit |
The fixed CAR shell family and flag class , with . |
atomicRepresentation (selectedRepresentation completedRootPureState) |
The coordinatewise representation on . The index set need not be countable. |
(atomicRepresentation ... (transportedFlag family i n)).range |
The linear subspace of the atomic Hilbert space. |
⨅ n, (...).range |
The intersection of those subspaces over all natural stages: . |
selectedEmbedding completedRootPureState i (selectedVector completedRootPureState i) |
The vector , where is the selected unit cyclic vector and embeds it in coordinate . |
ℂ ∙ ... |
The one-dimensional complex span of that vector. The whole equality says the common range is exactly this line, not the entire fiber . |
Further source notes: Here | |
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