Extends agreement from a convex interior to all source points by
continuity.
Statement
Let
be real normed spaces and let
be a bijective isometry between subsets. Assume
is convex, its interior in
is nonempty, and
Then there is a unique surjective real affine isometry
such that
for every
.
Assumptions
The stated interiors are ambient interiors, not relative interiors in
affine spans. Convexity is assumed only for
.
Both directions of the displayed interior-membership equivalence are
hypotheses for the given
.
Conclusion
The unique ambient affine extension agrees on all of
,
including points outside its interior. No separate target convexity or
completeness assumption is needed.
Proof route
Restrict the isometry to the two ambient interiors, use the open
connected theorem, and extend equality from the dense interior inside
the source set.
Proof steps
For
the forward implication puts
in
.
If
,
let
;
the reverse implication puts
in
.
Thus The
isometry restricted to ambient interiors gives a bijective isometry
,
with the original forward and inverse values.
The source interior is convex and nonempty, hence connected, and
both interiors are open. These verify every hypothesis of Open
connected extension theorem for the restricted isometry. It yields a
unique ambient affine isometry
with
on
.
Convexity and nonempty interior give
.
Concretely, choose
and
with
.
For
and
,
the point
satisfies
by convexity, and
as
.
Thus the interior points are dense in the subspace
,
the density step used in Extension
through a dense convex interior.
The two functions
and
are continuous. Their equality set is closed in
,
because
is a metric space, and contains the dense interior subset. Hence
for all
.
Any other extension restricts to an extension on the source interior;
uniqueness from Step 2 makes it equal to
.