Restricts a set isometry and its inverse to the two contained
lenses.
Statement
Let
be real normed spaces,
,,
and
a bijective isometry. Choose
and
.
Write
.
If
then
.
Assumptions
The half-distance bound and both displayed lens inclusions are
assumed for the same points, radius and isometry. There is no openness
or convexity requirement on
.
Conclusion
The midpoint belongs to
and its image is the midpoint of the two images. The target
half-distance bound is a consequence of distance preservation.
Proof route
Use both inclusions to restrict the forward and inverse maps; then
apply the lens midpoint theorem to that restriction.
Proof steps
If
,
then
and
Hence
lies in the target lens. Conversely, for
in that lens, the target inclusion allows
to be formed, and the same two distance identities put it in the source
lens. This is precisely the bijective isometry in Restriction
to corresponding lenses.
Distance preservation gives
.
The source half-distance bound and Midpoint
membership also give
.
Apply Midpoint
preservation between lenses to the restricted isometry, source foci
,
target foci
and radius
.
Both half-distance hypotheses were checked above. Since this restriction
evaluates to the original
,
its output is
.